27 Dec
2008
27 Dec
'08
3:37 a.m.
Hi, I can write: *Main> let yes = not . not *Main> :t yes yes :: Bool -> Bool But not: *Main> let isNotEqual = not . (==) <interactive>:1:23: Couldn't match expected type `Bool' against inferred type `a -> Bool' Probable cause: `==' is applied to too few arguments In the second argument of `(.)', namely `(==)' In the expression: not . (==) Why? Oscar