On Thu, 10 Jan 2008 10:22:03 +0200, Mitar
Hi!
Why is 0/0 (which is NaN) > 1 == False and at the same time 0/0 < 1 == False. This means that 0/0 == 1? No, because also 0/0 == 1 == False.
I understand that proper mathematical behavior would be that as 0/0 is mathematically undefined that 0/0 cannot be even compared to 1.
There is probably an implementation reason behind it, but do we really want such "hidden" behavior? Would not it be better to throw some kind of an error?
Mitar
I think it's a bug. Here is why: let f = (\x -> x/0) in f 0 == f 0 Referential transparency say that f 0 must equal to f 0, but in this case it is not. :-) ________ Information from NOD32 ________ This message was checked by NOD32 Antivirus System for Linux Mail Servers. part000.txt - is OK http://www.eset.com