Looks to me like you want:
poolNewsB = foldr poolNews (0,0,0,0)
On Nov 10, 2007 11:54 AM, Ryan Bloor
hiya
I was wondering how I would get the second function do recursively do the function for poolNews xs.... tried that and it fails.
Ryan
--Give wins, draws a rating.
poolNews :: Result -> PoolNews -> PoolNews
poolNews (a,b,c,d,e) (home,away,goaless,scoredraw)
| c > d = (home+1,away,goaless,scoredraw)
| c < d = (home,away+1,goaless,scoredraw)
|(c == 0) && (d == 0) = (home+1,away,goaless+1,scoredraw)
| otherwise = (home,away,goaless,scoredraw+1)
--Do for all Results
poolNewsB :: Results -> PoolNews poolNewsB (x:xs) = poolNews x (0,0,0,0)
________________________________ Get free emoticon packs and customisation from Windows Live. Pimp My Live! _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe