Peter Hercek
Achim Schneider wrote:
-- That's the one I've been looking for. Remember that -- return e = [e] f'''' = concatMap (\x -> concatMap (\y -> concatMap (\_ -> [(x,y)]) (if x*y == 8 then [()] else [])) [2..8]) [1..4]
Morale: Premature term elimination is the root of all misunderstanding.
Haskell wins the wickedness of design contest by using [()] and [] as truth values.
Maybe you wanted to say: "... by using [()] as True value and [] as False value" ... which does not seem that wicked (at least to me).
Strangely enough, it reads exactly the same to me. IMHO, not working like filter is the thing that makes this wicked: guard doesn't care about what is returned, you could as well say (\_ -> [("foo","bar")]) -- (c) this sig last receiving data processing entity. Inspect headers for past copyright information. All rights reserved. Unauthorised copying, hiring, renting, public performance and/or broadcasting of this signature prohibited.