Re: [Haskell-cafe] Question on "case x of g" when g is a function

27 Jan 2005


      On Thu, 27 Jan 2005 yeoh@cs.wisc.edu wrote:
...
Can a kind soul please enlighten me on why f bit0 and f bit1
both return 0?
...
bit0     = False
bit1     = True
f x = case x of
        bit0 -> 0
        bit1 -> 1
If you compile with 'ghc -Wall' GHC should report that the identifier
'bit0' in the case expression shadows the global 'bit0' identifier. What
you want to do is:

f x = if x == bit0 then 0 else 1

Re: [Haskell-cafe] Question on "case x of g" when g is a function

Henning Thielemann