
2011/3/8 Roel van Dijk
Hello everyone,
Hello!
But I lost the power of the context! How do I get it back?
The tagless interpreters splits the interpreter code (in your case, the 'eval' function) into multiple functions on one or more type classes. Now, the key insight is that your interpreter is actually not 'eval' but 'go' =), which has type 'Ctx -> a' (instead of just 'a'). But you don't need to change any code that uses Lit, Add and Mul, they work unmodified. First of all, I'll generalize your context a bit: data Ctx a = Empty | AddL a (Ctx a) | AddR a (Ctx a) | MulL a (Ctx a) | MulR a (Ctx a) deriving (Show) Now we can create a new interpreter: newtype CtxInterpA a = CIA {unCIA :: Ctx a → a} I'm appending A to its name because later on I'll propose another interpreter B. The underlying type 'a' is the same 'a' from your original 'eval' function, so we can't use 'lit' from 'Lit' type class. So we create class CtxLitA a where ctxLitA :: Integer → Ctx a → a Our interpreter's instance for 'Lit' is then simply instance CtxLitA a ⇒ Lit (CtxInterpA a) where lit = CIA∘ctxLitA To get a result from 'CtxInterpA a' we just pass an empty context: fromCtxInterpA :: CtxInterpA a → a fromCtxInterpA x = unCIA x Empty The 'Add' instance, however, is somewhat problematic. We need an 'a' for our 'Ctx a', however the arguments given for 'add' are of type 'CtxInterpA a'. To get an 'a' from 'CtxInterpA a' we need, again, a 'Ctx a'. instance Add a ⇒ Add (CtxInterpA a) where add x y = CIA (λctx → let x' = unCIA x (AddL y' ctx) y' = unCIA y (AddR x' ctx) in x' `add` y') The main problem with this instance with respect to your original 'eval' code is that in 'AddL' and 'AddR' we have y' and x', and not y and x. So y' and x' are mutually recursive. The Mul instance is similar. This may or may not be what you wanted on your original problem. Note, however, that there's a plan B. We can have different definitions of CtxLitA and CtxInterpA, this time using 'Ctx Exp': class CtxLitB a where ctxLitB :: Integer → Ctx Exp → a data CtxInterpB a = CIB {cibMake :: Ctx Exp → a ,cibExp :: Exp} Besides our function that creates 'a's, we also keep note of the corresponding 'Exp' and use it to create the 'Ctx Exp' without mutual recursion: instance CtxLitB a ⇒ Lit (CtxInterpB a) where lit i = CIB (ctxLitB i) (lit i) instance Add a ⇒ Add (CtxInterpB a) where add x y = CIB (λctx → let x' = cibMake x (AddL (cibExp y) ctx) y' = cibMake y (AddR (cibExp x) ctx) in x' `add` y') (add (cibExp x) (cibExp y)) The drawback of this approach should be obvious: we are tagging everything =). So this sort of defeats the tagless interpreter approach. I don't know if this solves your real problem, but it may be a start =). I'm attaching everything. Cheers, -- Felipe.