
29 Aug
2007
29 Aug
'07
5:10 p.m.
Hi
mapPairs :: (a -> a -> a) -> [a] -> [a] mapPairs f [x] = [x] mapPairs f [] = [] mapPairs f (x:xs) = f x (head xs) : mapPairs f (tail xs)
It looks like it works, but you can get a better version by changing the last line: mapPairs f (x:y:zs) = ... - left as an exercise, but no need for head or tail. Thanks Neil