Re: [Haskell-cafe] Shouldn't this loop indefinitely => take (last [0..]) [0..]

On Thu, Apr 3, 2008 at 10:35 PM, Bryan O'Sullivan wrote:

It's not an infinite list. It's a list of length maxBound::Int, as required by the fact that take's first argument is an Int. The second argument is probably defaulting to Integer.

Right! The first arg of "take" makes the first list into a int list. I did not wait long enough to see the end of the list and I'm so used to represent infinite lists with [0..] that I didn't think it could be limited. Thanks for the explanation! Olivier.