Re: [Haskell-cafe] Different semantics in "identical" do statement?

Daniel Peebles wrote:

I vaguely remember on IRC someone pointing out that the Parsec monad broke one of the laws. I think return _|_ >> x === _|_ which could be causing your problem. I may be wrong though.

This could very well be it. I use lazy eval to construct a function that returns its own argument (that is you supply the return value of the func as its arg). -- View this message in context: http://www.nabble.com/Different-semantics-in-%22identical%22-do-statement--t... Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.