Re: [Haskell-cafe] Error with Float

Perhaps you mean: f x | x < 1 = 0 : f (2*x) | otherwise = 1 : f (2*(x-1)) Note that in the second case, the 1 is subtracted before multiplication by 2. If you were referring to the problem that this eventually gives constantly 0 for values like 0.6, try importing the Ratio module and applying it to 6%10, which is the exact rational value rather than a floating point representation. - Cale On 19/07/05, Dinh Tien Tuan Anh wrote:

This is my function to convert a fraction (0

f x ¦t<1 = 0::f t ¦otherwise = 1::f (t-1) where t = 2*x

I guess there's nothing wrong with that, but when traced, it has something like 0.6*2 - 1 = 0.600001 This error got accumulated and made my f function wrong (will eventually evaluate an infinite 0, no matter what value of x)

Please tell me there's some ways to deal with that.

Thanks a lot

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