Re: [Haskell-cafe] How to present the commonness of some objects?

On Thu, Jul 2, 2009 at 8:32 PM, Magicloud Magiclouds < magicloud.magiclouds@gmail.com> wrote:

Wow, this complex.... Thank you. I will try that.

No, don't! There is an easier way. Don't use a class, just use a record. I would translate your class as: data Widget = Widget { widgetRun :: IO () } If you need more capabilities, add them as fields in this record. There is no need for typeclasses here. Keep in mind that with this solution *and* with the ExistentialQuantification solution, there is no possibility of downcasting. I.e. if you were planning on making a GraphicalWidget subclass, and them somewhere seeing if a a Widget is actually a GraphicalWidget, you will be disappointed. The solution in this case is to redesign your software not to need downcasting. This is the point at which you are forced to move away from OO thinking. Luke

On Fri, Jul 3, 2009 at 12:24 PM, Ross Mellgren wrote:

...

You have a couple problems here.

The first is that GHC has no idea what particular type 'w' widgetList has, because the empty list is polymorphic.

The second is that it looks like you probably want a heterogeneous list of widgets -- that is, possibly different types of widget as long as they all conform to Widget. To do this you'll need ExistentialQuantification (or GADTs I guess?).

For example:

{-# LANGUAGE ExistentialQuantification #-}

class Widget w where widgetRun :: w -> IO ()

data SomeWidget = forall w. Widget w => SomeWidget w

widgetList :: [(Integer, Integer, SomeWidget)] widgetList = []

main = mapM aux widgetList aux (x, y, sw) = case sw of SomeWidget w -> widgetRun w

Note that the type variable for widgetList 'w' has disappeared. Before, with the type variable 'w', all elements of the widgetList had to be of the same type (lists being homogeneous). By wrapping up the type variable 'w' inside SomeWidget, you can now have whatever types of widgets in that SomeWidget, e.g.

data Button = Button (IO ()) instance Widget Button where widgetRun = ...

data Label = Label (String -> IO ()) instance Widget Label where widgetRun = ...

widgetList:: [(Integer, Integer, SomeWidget)] widgetList = [ SomeWidget (Button $ putStrLn "ding!") , SomeWidget (Label $ putStrLn . ("entered: " ++)) ]

Before, without existential quantification, you had to have all the same type of widget (e.g. all Button or all Label)

Hope this makes it more clear.

-Ross

On Jul 3, 2009, at 12:00 AM, Magicloud Magiclouds wrote:

...

Hi, I thought "class" was for this purpose. But it turns out not. Code as following could not compiled.

1 main = do 2 mapM_ (\(x, y, widget) -> do 3 a <- widgetRun widget 4 putStrLn $ show a 5 ) widgetList 6 7 widgetList :: (Widget w) => [(Integer, Integer, w)] 8 widgetList = [] 9 10 class Widget w where 11 widgetRun :: w -> IO () --- % ghc --make tmp/test.hs [1 of 1] Compiling Main ( tmp/test.hs, /tmp/Main.o )

tmp/test.hs:3:16: Ambiguous type variable `t' in the constraint: `Widget t' arising from a use of `widgetRun' at tmp/test.hs:3:16-31 Probable fix: add a type signature that fixes these type variable(s) -- 竹密岂妨流水过 山高哪阻野云飞 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe

-- 竹密岂妨流水过 山高哪阻野云飞 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe