
I know functions can be compared in Scheme Welcome to DrScheme, version 4.1 [3m]. Language: Swindle; memory limit: 128 megabytes.
(equal? equal? equal?) #t
but apparently not in Haskell
[michael@localhost ~]$ ghci
GHCi, version 6.10.1: http://www.haskell.org/ghc/ :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer ... linking ... done.
Loading package base ... linking ... done.
Prelude> (==) (==) (==)
<interactive>:1:0:
No instance for (Eq (a -> a -> Bool))
arising from a use of `==' at <interactive>:1:0-13
Possible fix: add an instance declaration for (Eq (a -> a -> Bool))
In the expression: (==) (==) (==)
In the definition of `it': it = (==) (==) (==)
Prelude>
though I'm new at Haskell and may not be posing the question properly.
I would think a language with 1st-class support for functions would
certainly include comparing them.
To compare two functions in C, I would compare their machine addresses.
Michael
--- On Sat, 4/18/09, Eugene Kirpichov
Though I haven't tried it out, it's trying to use my function to count functions.
The first argument is the identity function.
The second argument is a list of a different form of the identity function.
Though the two identity functions, given the same input, would produce the same output, I doubt they would be equal.
So my guess at an answer would be zero.
Michael
--- On Sat, 4/18/09, Eugene Kirpichov
wrote: From: Eugene Kirpichov
Subject: Re: [Haskell-cafe] General function to count list elements? To: "michael rice" Cc: haskell-cafe@haskell.org Date: Saturday, April 18, 2009, 11:03 AM What should
count (\x -> x) (replicate 10 (\y -> if 1==1 then y else undefined))
return?
2009/4/18 michael rice
: Is there a general function to count list elements. I'm trying this
count :: a -> [a] -> Int count x ys = length (filter (== x) ys)
with this error upon loading
=============
[michael@localhost ~]$ ghci count GHCi, version 6.10.1: http://www.haskell.org/ghc/ :? for help Loading package ghc-prim ... linking ... done. Loading package integer ... linking ... done. Loading package base ... linking ... done. [1 of 1] Compiling Main ( count.hs, interpreted )
count.hs:2:29: Could not deduce (Eq a) from the context () arising from a use of `==' at count.hs:2:29-32 Possible fix: add (Eq a) to the context of the type signature for `count' In the first argument of `filter', namely `(== x)' In the first argument of `length', namely `(filter (== x) ys)' In the expression: length (filter (== x) ys) Failed, modules loaded: none. Prelude>
=============
Not sure what it's trying to tell me other than I need an (Eq a) somewhere.
Michael
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-- Eugene Kirpichov Web IR developer, market.yandex.ru
-- Eugene Kirpichov Web IR developer, market.yandex.ru