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Simon Marlow wrote:
Yes, except that you forgot that not all foreign calls can run concurrently with Haskell code. Only the "safe" ones can.
Yes, except that you forgot that not all foreign calls can run
concurrently with Haskell code. Only the "safe" ones can.
Okay, now I understand what is going on. Why is there extra overhead for a 'safe' call? Keean. //
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