Hello Cafe, I'm about to introduce UUID into my code, and see https://github.com/haskell-hvr/uuid/issues/24 https://github.com/haskell-hvr/uuid/issues/24 stating:
Currently, UUID is represented as data UUID = UUID {-# UNPACK #-} !Word32 {-# UNPACK #-} !Word32 {-# UNPACK #-} !Word32 {-# UNPACK #-} !Word32 However, this suboptimal for 64bit archs (where GHC currently stores this a 320-byte Heap object); ...
According to https://wiki.haskell.org/GHC/Memory_Footprint https://wiki.haskell.org/GHC/Memory_Footprint I can understand each evaluated `Word32` on 64-bit hardware can take 2 words - 16 bytes, and given they are unpacked and strict, I think one whole UUID record should just take 64 bytes plus a few words, which is far less than 320 bytes. So how comes the 320 bytes? Thanks with regards, Compl