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Jonas, 2010/10/13 Jonas Almström Duregård
(++) :: Finite s1 a -> Finite s2 a -> Finite (S (Plus s1 s2)) a (++) (Finite a) (Finite b) = Finite $ a Prelude.++ b infixr 5 ++
Why do you have the S in the return type of Finite.++ ? Ozgur
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