"rodrigo.bonifacio"
Dear Sirs,
I guess this is a very simple question. How can I convert IO [XmlTree] to just a list of XmlTree?
unsafeCoerce. Seriously, you just don't, you weld stuff together using >>=. It takes an 'IO a' and a function 'a -> IO b' and returns you an 'IO b', thus preventing you from launching nuclear missiles while you're standing in front of the exhaust jets. You don't want to be able to. do-notation is a convenient short-hand: foo >>= (\bar -> return $ baz bar) do bar <- foo return $ baz bar
= doesn't only work with IO, but with any monad, that's why it's type,
(>>=) :: Monad m => m a -> (a -> m b) -> m b might look intimidating, but actually isn't. For more info, have a look at Real World Haskell[1], and, after that, the Typeclassopedia[2]. As a final notice, don't listen to the others: Those are just desperate people, vainly trying to convince themselves they'd understand monads. If you see monads being compared to space suits, nuclear waste processing plants, or burritos, run far, run fast, but run. If you see them compared to applicative functors, get curious. [1]http://book.realworldhaskell.org/read/ [2]http://byorgey.wordpress.com/2009/02/16/the-typeclassopedia-request-for-feed... -- (c) this sig last receiving data processing entity. Inspect headers for copyright history. All rights reserved. Copying, hiring, renting, performance and/or quoting of this signature prohibited.