Re: [Haskell-cafe] Couple of questions about *let* within *do*

So all the Xs would be in scope at s6. Important point. Thanks, Michael --- On Tue, 8/10/10, Alex Stangl wrote: From: Alex Stangl Subject: Re: [Haskell-cafe] Couple of questions about *let* within *do* To: "michael rice" Cc: "Tillmann Rendel" , haskell-cafe@haskell.org Date: Tuesday, August 10, 2010, 2:21 PM On Tue, Aug 10, 2010 at 11:01:28AM -0700, michael rice wrote:

Hi all,

Then,

   do s1       s2       let x1 = e1           x2 = e2       s3       s4       let x3 = e3           x4 = e4       s5       s6

becomes

   do s1       s2       let x1 = e1           x2 = e2 in do s3                         s4       let x3 = e3           x4 = e4 in do s5                         s6?

    do s1        s2        let x1 = e1            x2 = e2        in do s3              s4              let x3 = e3                  x4 = e4              in do s5                    s6 HTH, Alex