hi ALL, I think I've found a mistake in foldt implementation on the Fold page[1] of the HaskellWiki. foldt :: (a -> a -> a) -> a -> [a] -> a foldt f z [] = z foldt f z [x] = x -- mistake? -- foldt f z [x] = f x z -- fix proposal foldt f z xs = foldt f z (pairs f xs) pairs :: (a -> a -> a) -> [a] -> [a] pairs f (x:y:t) = f x y : pairs f t pairs f t = t Without the fix, foldt just ignores z value in all cases except for the case of empty input list. (Which is an inconsistent behaviour I suppose.) The Examples page[2] also needs corresponding fix. Is this mail list a right place to ask for the HaskellWiki page fix? Thanks! Michael. [1] Tree-like folds @ Fold @ HaskellWiki https://wiki.haskell.org/Fold#Tree-like_folds [2] Examples @ Fold @ HaskellWiki https://wiki.haskell.org/Fold#Examples -- Michael V. Antosha http://mivael.in.ua xmpp:m@mivael.in.ua (Jabber ID)