Thanks. My question is whether it can call a function (say map) previously
defined elsewhere in the program. Same goes for filter.
Tope
On Fri, Feb 22, 2008 at 6:04 AM, Christian Maeder
I know the following:
[1] That the general form of conditional expression is: if *Boolean_expression* then /exp1/ else /exp2 /[2] That a conditional expression must always have both a then and an else expression. [3] That both /exp1/ and /exp2/ must have the same type, which is the type of the entire conditional expression. [4] That /exp1/ must be <true-value> and /exp2/ must be <false-value>
Reference: Discrete Mathematics Using Computer by John O'Donnell and et al. (Second Edition)
My question: Is it possible that exp1 and exp 2 be different function calls of another functions (separately) elsewhere within the same
TOPE KAREM wrote: program?
Note: My Boolean_expression is Boolean My /exp1/ is a function call elsewhere within the same program (more like a subroutine) My /exp2/ is another function call also elsewhere within the same program.
I'm not sure what you're asking, but exp1 and exp2 may have (the same) function type:
if <cond> then map else filter :: (Bool -> Bool) -> [Bool] -> [Bool]
HTH Christian