
4 Jan
2012
4 Jan
'12
8:46 a.m.
On Wed, Jan 4, 2012 at 9:41 PM, Yves Parès
Would you try:
f :: a -> a f x = undefined :: a
And tell me if it works? IMO it doesn't.
It works. As I understand, in this situation we are specializing the 'undefined :: forall a. a' to a more specific dependent type.