Re: [Haskell-cafe] How to get a file path to the program invoked?

On Thu, Dec 1, 2011 at 2:12 PM, dokondr wrote:

Hi, When my program starts it needs to know a complete path to the directory from which it was invoked. In terms of standard shell (sh) I need the Haskell function that will do equivalent to:

#!/bin/sh path=$(dirname $0)

How to get this path in Haskell?

If I understand you correctly, you want takeDirectory `fmap` getProgName where import System.FilePath (takeDirectory) Cheers, -- Felipe.