Brian Denheyer
doEvent f usDelay = forkIO $ threadDelay usDelay doEvent f usDelay f
There's a missing 'do' here, right?
Infinite loop? yes, that is what you wanted. Memory gobbling? Why would you think that?
Why would I think that ?
doEvent f usDelay = do forkIO $ threadDelay usDelay doEvent f usDelay f
Are you sure this isn't interpreted as: doEvent f usDelay = do (forkIO $ threadDelay usDelay) doEvent f usDelay f I.e. just forking off processes that only does a delay, never even getting to 'f'? I interpreted Thomas's code to mean: doEvent f usDelay = forkIO $ (do threadDelay usDelay doEvent f usDelay f) Which appears to work nicely here. -k -- If I haven't seen further, it is by standing in the footprints of giants