
Thanks you Ivan and David for clarifying this. Best Regards, Chris On Sat, Sep 18, 2010 at 3:55 AM, Ivan Lazar Miljenovic < ivan.miljenovic@gmail.com> wrote:
Hello Haskell Community -
I am a professional programmer with 11 years experience, yet I just do not seem to be able to get the hang of even simple things in Haskell. I am trying to write a function that takes a list and returns the last n elements.
There may be a function which I can just call that does that, but I am trying to roll my own just to understand the concept.
Let's call the function n_lastn and, given a list [1,2,3,4,5], I would
n_lastn 3 = [3,4,5]
Seems like it would be something like:
n_lastn:: [a]->Int->[a] n_lastn 1 (xs) = last(xs) n_lastn n (x:xs) = ????
The issue is I do not see how you can store the last elements of the
On 18 September 2010 17:51, Christopher Tauss
wrote: like list. Easiest way I can think of:
n_lastn n = reverse . take n . reverse
Alternatively:
n_lastn n xs = drop (len - n) xs where len = length xs
-- Ivan Lazar Miljenovic Ivan.Miljenovic@gmail.com IvanMiljenovic.wordpress.com http://ivanmiljenovic.wordpress.com/