26 Aug
2003
26 Aug
'03
3:49 p.m.
Am Dienstag, 26. August 2003 05:54 schrieb Matt Harden:
Cool! That leads me to this contraption:
tricky = 0 : enigma tricky tricky enigma (k : ks) = (k :) . labyrinth (enigma ks) labyrinth f (k : _ : ks) = (k + 1) : f ks
Figure out what `tricky' is, and what its relationship is to `unknown'.
Well, `tricky' can be defined much simpler:
tricky = [0 ..] \/ tricky
where `\/' denotes ... (I leave this to the imagination of the reader). Cheers, Ralf