3 Aug
2007
3 Aug
'07
3:26 p.m.
On 8/3/07, Neil Mitchell
Can you use (<-) outside of a do block? b >> f (<- a)
b >> do { ta <-a; f ta } or b >> a >>= \ta -> f ta
What are the semantics of do b >> f (<- a)
do b >> a >>= \ta -> f ta
Given:
if (<- a) then f (<- b) else g (<- c)
a >>= \ta -> if (ta) then ( b >>= \tb -> f tb ) else ( c >>= \tc -> f tc )
do let x = (<- a) f x
No idea if that could be possible. or maybe : do a >>= \ta -> let x = ta in f x _______________________________________________
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