
3 Mar
2011
3 Mar
'11
7:39 p.m.
Excerpts from Jacek Generowicz's message of Fri Mar 04 00:18:07 +0000 2011:
Prelude Data.List> groupBy (<) [1,2,3,2] [[1,2,3,2]] This is wired. However if you think about the algorithm always using the first element of a list and comparing it against the next elements you get
1 < 2 ok, same group 1 < 3 dito 1 < 2 dito Thus you get [[1,2,3,2]] Marc Weber