Re: [Haskell-cafe] How to fix ambiguous type variable?

On 6/13/19 6:36 AM, Boris wrote:

someCheck :: (Show a, Read a, Eq a) => String -> a -> Bool someCheck s v = (read . show . read $ s) == v

someCheck :: (Show a, Read a, Eq a) => String -> a -> Bool someCheck s v = (r . show . r $ s) == v where r = read I believe you do intend to use the same read in both cases anyway, and letting a different read to slip in would be a bug. Marian