21 Dec
2005
21 Dec
'05
3:51 p.m.
On Wed, 21 Dec 2005, Scherrer, Chad wrote:
------------ From: Daniel Carrera
Hey,
The sqrt function is not doing what I want. This is what I want:
round sqrt(2) --------------------------------------------------- Daniel,
A lot of Haskell folks like to avoid parentheses as much as possible, and there's a really convenient way to do this. There is a Prelude function ($) f x = f x which is right-associative, so you can write round $ sqrt x == round (sqrt x) This becomes really convenient when multiple application is involved: print $ round $ sqrt x == print (round (sqrt x))
Doesn't it sometimes feel like the $ operator is Haskell's way of saying "We're not with those Lisp guys, seriously"?