Hi All, Referring to the following, which is taken from the *Control.Newtype *documentation page: op :: Newtypehttp://hackage.haskell.org/packages/archive/newtype/0.2/doc/html/Control-New... n o => (o -> n) -> n -> oSourcehttp://hackage.haskell.org/packages/archive/newtype/0.2/doc/html/src/Control... This function serves two purposes: 1. Giving you the unpack of a newtype without you needing to remember the name. 2. Showing that the first parameter is *completely ignored* on the value level, meaning the only reason you pass in the constructor is to provide type information. Typeclasses sure are neat. As point #2, above, emphasizes, the only purpose for the first argument to the function (i.e. - the constructor "(o -> n)") is to specify the type of 'n'. However, being a *newtype*, 'n' can have only one constructor. So, why is it necessary to pass in the constructor to this function, when we're already passing in 'n'? Thanks, -db