Re: [Haskell-cafe] Re: howto tuple fold to do n-ary cross product?

On Mon, Nov 24, 2008 at 7:40 AM, Andrea Vezzosi wrote:

It's more natural to consider the cross product of no sets to be [[]] so your crossr becomes:

crossr [] = [[]] crossr (x:xs) = concat (map (\h ->map (\t -> h:t) (crossr tail)) hd

Ops, hd and tail should be x and xs here.