11 Jul
2013
11 Jul
'13
2:45 p.m.
On Thu, Jul 11, 2013 at 2:11 PM, Vlatko Basic
The problem here isn't quite what you think it is; (==) is not a constructor, therefore it is a *variable*. It's exactly the same problem as
a = 5 -- ... foo a = 3 -- this does NOT compare with the previous value of "a"; it's identical to the next line! foo x = x
Hm, I thought it is a pattern match with constant, as in f ('a':xs) ==
I wonder what you'd make of this definition, then? (*) `on` f = \x y -> f x * f y -- brandon s allbery kf8nh sine nomine associates allbery.b@gmail.com ballbery@sinenomine.net unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net