1 Oct
2008
1 Oct
'08
3:35 a.m.
On Tue, 30 Sep 2008 19:54:17 +0200, Adrian Neumann
I often wonder how many cuts you need to divide a steak in n pieces. You can obviously get n pieces with (sqrt n) cuts by cutting a grid. But I'm sure some smart mathematician thought of a (log n) way.
Good thing that the chocolate slab was only 2 kg and of finite length. Had it been of infinite length, we would need Dedekind cuts to partition it.... ;) -- Benjamin L. Russell