Re: [Haskell-cafe] Why no IO transformer monad?

I thought you would get the following if you have a transformer 'M': runM :: M IO a -> IO a to run 'M'... Keean. Udo Stenzel wrote:

Keean Schupke schrieb am 20.12.04 10:25:36:

...

What about:

runIOT :: Monad m => IOT m a -> IO (m a)

I have a gut feeling that this is unimplementable. However, IO (m a) is what you get using the transformer version of m over IO.

Udo.

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