
22 Feb
2009
22 Feb
'09
1:31 a.m.
On Sat, Feb 21, 2009 at 10:26 PM, Phil
Thanks for the tip - I got it to work using:
a :: UArray Int Double
.... And so on.
That's nice. I should have noted as well that you may say just a, b, c, d :: UArray Int Double or, even better, type DataArray = UArray Int Double a, b, c, d :: DataArray And yes, that "UArray (Int,Int) Double" was a typo, sorry =). Cheers, -- Felipe.