On 2/12/06, Chatzianastassiou Achilleas
In addition to my previous quote, I don't understand the user of fromIntegral At the prelude, when i type i.e. fromIntegral 4 it returns 4 Thanks
fromIntegral is overloaded. It will convert an Integral value (such as Int or Integer) to a numeric value (such as Double, Float, but also Integer and Int). When you type "fromIntegral 4" it will default the 4 to be an Integer, and it will default the result to be an integer as well. Try typing "fromIntegral 4 :: Double", indicating that the result should be a double, that will give you 4.0. I think this version will work better... Take the logarithm (in base 10) to find out how many digits to the left of the decimal point there is (and subract it from the "shift" amount). This can give negative shifts, so we use (**) instead of (^) since the latter can't deal with negative exponents. myround n s = fromIntegral (round (n * factor)) / factor where shift = s - (floor (logBase 10 n) + 1) factor = 10 ** fromIntegral shift -- Sebastian Sylvan +46(0)736-818655 UIN: 44640862