
What about f <$!> x = (f $!) <$> x ? --Will
On Aug 10, 2015, at 14:20, Christopher Allen
wrote: http://stackoverflow.com/questions/9423622/strict-fmap-using-only-functor-no... seems to cover it.
On Mon, Aug 10, 2015 at 4:17 PM, Alexey Egorov
wrote: Hello haskellers, I wonder why <$> and <$!> have different typeclass constraints?
(<$>) :: Functor f => (a -> b) -> f a -> f b (<$!>) :: Monad m => (a -> b) -> m a -> m b _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe
-- Chris Allen Currently working on http://haskellbook.com _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe