21 Oct
2008
21 Oct
'08
1:28 a.m.
Is there a simple way to do this, i.e. using existing libraries?
Yes indeed. I'll be traveling over the next two days, and am shooting for a fully functional hackage release by mid next week.
What I need is a Haskell expression parser which outputs values of type Language.Haskell.TH.Syntax.QExp, but I can't see one available in the TH libraries, or in the haskell-src(-exts) libraries.
My strategy is to use the existing haskell-src-exts parser, then translate that AST to the TH AST. Once I've got settled in one place, I'll follow up with a brain dump :)
Cheers, Reiner
Matt