Re: [Haskell-cafe] "computational time" always 0.0 in this example...

7 Dec 2006

      Hello Lennart,

Thursday, December 7, 2006, 4:59:57 PM, you wrote:
...
time $ product [1..1000] `seq` return ()
instead of
time $ doTest wordList2 wordList2 `seq` return ()
works fine.
because 'product' returns just one value. use the following:

time $ (return $! last (doTest wordList2 wordList2))

-- 
Best regards,
 Bulat                            mailto:Bulat.Ziganshin@gmail.com

Re: [Haskell-cafe] "computational time" always 0.0 in this example...

Bulat Ziganshin