Re: [Haskell-cafe] Order of evaluation

On Thursday 26 July 2007, Jon Harrop wrote:

If you have a boolean-or expression:

a || b

will "a" be evaluated before "b" in Haskell as it is in other languages?

Yes. The definition of (||) is roughly True || b = True False || b = b Which de-sugars to (||) = \ a b -> case a of True -> True False -> b Which does exactly what you want. Jonathan Cast http://sourceforge.net/projects/fid-core http://sourceforge.net/projects/fid-emacs