Re: [Haskell-cafe] Map list of functions over a single argument

Quoth Paul Moore, nevermore,

...

Prelude> map ($ 3) [(*2),(+1),div 1] [6,4,0]

Cool. I told you I was missing something! :-)

I suppose this would fit your original idea if you wanted that particular type signature. (Warning: not tested.)

f :: a -> [a -> b] -> [b] f c fs = map ($ c) fs

mapF :: [a -> b] -> a -> [b] mapF = flip f

Aren't higher order functions just dreamy... ? ;-) -- Dougal Stanton