map f xs = [ f x | x <- xs ]
On Tue, Apr 14, 2009 at 11:21 AM, Tsunkiet Man
Let's see...
cinits [] = [[]] cinits (hd:tl) = [] : [ hd : rest | rest <- cinits tl ]
Well, ehm, I'm trying to understand "map" in "map" functions, however I do understand list comprehensions. But I don't think I can write "any" "map" in "map" function into a list comprehension can I?
2009/4/14 Daniel Fischer
Am Dienstag 14 April 2009 10:39:28 schrieb Tsunkiet Man:
Hello,
I can hardly imagine how the following code works:
cinits :: [a] -> [[a]] cinits [] = [[]] cinits (x:xs) = [] : map (x:) (cinits xs)
can someone give me a good explaination?
Perhaps it's easier to follow as a list comprehension:
cinits [] = [[]] cinits (hd:tl) = [] : [ hd : rest | rest <- cinits tl ]
(I understand it a bit, but it's really hard for me to figure out how a map in a map function works.)
Thank you for your time,
Tsunkiet
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