[Haskell-cafe] Haskell safe ccalls

17 Dec 2015

      Hi everybody,

I’m new on this list and have a newbie question about Haskell FFI and safe calls.
I have written the following lines of C code that rely on the RTS:

Condition* init_cond(){
	Condition* c = malloc(sizeof(Condition));
	initCondition(c);
	return c;
}

Mutex* init_mutex(){
	Mutex* m = malloc(sizeof(Mutex));
	initMutex(m);
	return m;
}

void wait_condition(Condition* condition, Mutex* mutex) {
	ACQUIRE_LOCK(mutex);
	if(!waitCondition(condition, mutex)){
		fprintf(stderr, "A: Wait failed!");
	};
	RELEASE_LOCK(mutex);
}

And the Haskell program is written as follow:

data Condition = Condition
data Mutex = Mutex
foreign import ccall "init_cond" init_cond :: IO (Ptr Condition)
foreign import ccall "init_mutex" init_mutex :: IO (Ptr Mutex)
foreign import ccall "wait_condition" wait_condition:: Ptr Condition -> Ptr Mutex -> IO ()

main :: IO ()
main = do
    c <- init_cond
    m <- init_mutex
    wait_condition c m
    putStrLn “Hello!”

The behaviour that i want from my application is the same as the following C program:

int main(int argc, char** argv){
	pthread_cond_t c = PTHREAD_COND_INITIALIZER;
	pthread_mutex_t m;
	pthread_mutex_init(&m, 0);
	pthread_mutex_lock(&m);
	pthread_cond_wait(&c, &m);
	printf(“I didn’t block!\n");
	pthread_mutex_unlock(&m);
	return 0;
}

What I expect is that the program doesn’t reach the putStrLn line, but it prints “Hello!” and terminates with exit code 0.

I can’t figure out what’s going on under the hood. 
Can someone explain me what i’m missing? (I’m familiar with Capabilities, Tasks, Haskell threads)

Thanks,
Valentino P.

[Haskell-cafe] Haskell safe ccalls

Valentino Picotti