It sounds like you're doing exactly what I'm looking for. I look forward to
more.
Reiner
On Tue, Oct 21, 2008 at 4:28 PM, Matt Morrow
Is there a simple way to do this, i.e. using existing libraries?
Yes indeed. I'll be traveling over the next two days, and am shooting for a fully functional hackage release by mid next week.
What I need is a Haskell expression parser which outputs values of type Language.Haskell.TH.Syntax.QExp, but I can't see one available in the TH libraries, or in the haskell-src(-exts) libraries.
My strategy is to use the existing haskell-src-exts parser, then translate that AST to the TH AST.
Once I've got settled in one place, I'll follow up with a brain dump :)
Cheers, Reiner
Matt _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe