Re: [Haskell-cafe] matrix computations based on the GSL

On Fri, 8 Jul 2005, Keean Schupke wrote:

So the linear operator is translation (ie: + v)... effectively 'plus' could be viewed as a function which takes a vector and returns a matrix (operator)

(+) :: Vector -> Matrix

Since a matrix _is_ not a linear map but only its representation, this would not make sense. As I said (v+) is not a linear map thus there is no matrix which represents it. A linear map f must fulfill f 0 == 0 But since v+0 == v the function (v+) is only a linear map if 'v' is zero. I can't see how to fit in your vector extension by the 1-component.