
Am Sonntag, 2. Juli 2006 01:58 schrieb Brent Fulgham:
We recently began considering another benchmark for the shootout, namely a Magic Square via best-first search. This is fairly inefficient, and we may need to shift to another approach due to the extremely large times required to find a solution for larger squares.
A slightly less naive approach to determining the possible moves dramatically reduces the effort, while Josh Goldfoot's code did not finish within 4 1/2 hours on my machine, a simple modification (see below) reduced runtime for N = 5 to 4.3 s, for N = 6 to 86.5 s. Unfortunately, the squares are now delivered in a different order, so my programme would probably be rejected :-(
I thought the Haskell community might be interested in the performance we have measured so far (see "http:// shootout.alioth.debian.org/sandbox/fulldata.php? test=magicsquares&p1=java-0&p2=javaclient-0&p3=ghc-0&p4=psyco-0"
Interestingly, Java actually beats the tar out of GHC and Python for N=5x5 (and I assume higher, though this already takes on the order of 2 hours to solve on the benchmark machine). Memory use in GHC stays nice and low, but the time to find the result rapidly grows.
I was hoping for an order of magnitude increase with each increase in N, but discovered that it is more like an exponential...
Thanks,
-Brent
Modified code, still best-first search: import Data.Array.Unboxed import Data.List import System.Environment (getArgs) main :: IO () main = getArgs >>= return . read . head >>= msquare msquare :: Int -> IO () msquare n = let mn = (n*(n*n+1)) `quot` 2 grd = listArray ((1,1),(n,n)) (repeat 0) unus = [1 .. n*n] ff = findFewestMoves n mn grd unus ini = Square grd unus ff (2*n*n) allSquares = bestFirst (successorNodes n mn) [ini] in putStrLn $ showGrid n . grid $ head allSquares data Square = Square { grid :: UArray (Int,Int) Int , unused :: [Int] , ffm :: ([Int], Int, Int, Int) , priority :: !Int } deriving Eq instance Ord Square where compare (Square g1 _ _ p1) (Square g2 _ _ p2) = case compare p1 p2 of EQ -> compare g1 g2 ot -> ot showMat :: [[Int]] -> ShowS showMat lns = foldr1 ((.) . (. showChar '\n')) $ showLns where showLns = map (foldr1 ((.) . (. showChar ' ')) . map shows) lns showGrid :: Int -> UArray (Int,Int) Int -> String showGrid n g = showMat [[g ! (r,c) | c <- [1 .. n]] | r <- [1 .. n]] "" bestFirst :: (Square -> [Square]) -> [Square] -> [Square] bestFirst _ [] = [] bestFirst successors (front:queue) | priority front == 0 = front : bestFirst successors queue | otherwise = bestFirst successors $ foldr insert queue (successors front) successorNodes n mn sq = map (place sq n mn (r,c)) possibilities where (possibilities,_,r,c) = ffm sq place :: Square -> Int -> Int -> (Int,Int) -> Int -> Square place (Square grd unus _ _) n mn (r,c) k = Square grd' uns moveChoices p where grd' = grd//[((r,c),k)] moveChoices@(_,len,_,_) = findFewestMoves n mn grd' uns uns = delete k unus p = length uns + len findFewestMoves n mn grid unus | null unus = ([],0,0,0) | otherwise = (movelist, length movelist, mr, mc) where openSquares = [(r,c) | r <- [1 .. n], c <- [1 .. n], grid ! (r,c) == 0] pm = possibleMoves n mn grid unus openMap = map (\(x,y) -> (pm x y,x,y)) openSquares mycompare (a,_,_) (b,_,_) = compare (length a) (length b) (movelist,mr,mc) = minimumBy mycompare openMap possibleMoves n mn grid unus r c | grid ! (r,c) /= 0 = [] | otherwise = intersect [mi .. ma] unus -- this is the difference that -- does it: better bounds where cellGroups | r == c && r + c == n + 1 = [d1, d2, theRow, theCol] | r == c = [d1, theRow, theCol] | r + c == n + 1 = [d2, theRow, theCol] | otherwise = [theRow, theCol] d1 = diag1 grid n d2 = diag2 grid n theRow = gridRow grid n r theCol = gridCol grid n c lows = scanl (+) 0 unus higs = scanl (+) 0 $ reverse unus rge cg = let k = count0s cg - 1 lft = mn - sum cg in (lft - (higs!!k),lft - (lows!!k)) (mi,ma) = foldr1 mima $ map rge cellGroups mima (a,b) (c,d) = (max a c, min b d) gridRow grid n r = [grid ! (r,i) | i <- [1 .. n]] gridCol grid n c = [grid ! (i,c) | i <- [1 .. n]] diag1 grid n = [grid ! (i,i) | i <- [1 .. n]] diag2 grid n = [grid ! (i,n+1-i) | i <- [1 .. n]] count0s = length . filter (== 0) Cheers, Daniel -- "In My Egotistical Opinion, most people's C programs should be indented six feet downward and covered with dirt." -- Blair P. Houghton