
7 Oct
2009
7 Oct
'09
4:41 p.m.
On Wed, Oct 7, 2009 at 12:08 PM, Ben Franksen
More generally, any ring with multiplicative unit (let's call it 'one') will do.
Isn't that every ring? As I understand it, the multiplication in a
ring is required to form a monoid.
--
Dave Menendez