Re: [Haskell-cafe] turning an imperative loop to Haskell

On 06/09/07, Axel Gerstenberger wrote:

Thanks to all of you. The suggestions work like a charm. Very nice.

I still need to digest the advices, but have already one further question: How would I compute the new value based on the 2 (or even more) last values instead of only the last one?

[ 2, 3 , f 3 2, f((f 3 2) 3), f ( f((f 3 2) 3) f 3 2)), ...]

foo = 2 : 3 : zipWith f (drop 1 foo) foo There's also zipWith3 etc. for functions with more arguments. -- Sebastian Sylvan +44(0)7857-300802 UIN: 44640862