
Luke, does your explanation to Guenther have anything to do with
coinduction? -- the property that a producer gives a little bit of
output at each step of recursion, which a consumer can than crunch in
a lazy way?
I find that coinduction seems to figure frequently in algos that
process a stream.
So, Guenther, I'm not certain if coinduction figures in here yet but
it gives you another thing to google on. Co-induction seems to play
the same role for stream processing in haskell that tail recursiveness
plays in non-lazy languages
like lisp. That is, it's kind of the ideal to be striven for. Whereas
in haskell, tail recursive is frequently not the best thing because it
goes into a non-terminating state when there is an infinite data
structure which is crunched down to a finite one but at the wrong
point in the function pipeline.
see http://groups.google.com/group/fa.haskell/browse_thread/thread/4240bc7c7abd4d30/49f28f5a41519335?q="it+is+however+nicely+coinductive"#49f28f5a41519335
2009/3/26 Luke Palmer
On Thu, Mar 26, 2009 at 12:21 PM, GüŸnther Schmidt
wrote:y Hi guys,
I tried for days now to figure out a solution that Luke Palmer has presented me with, by myself, I'm getting nowhere.
Sorry, I meant to respond earlier.
They say you don't really understand something until you can explain it to a six year old. So trying to explain this to a colleague made me realize how little I must understand it :-). But I'll try by saying whatever come to mind...
Lazy list processing is all about right associativity. We need to be able to output some information knowing that our input looks like a:b:c:..., where we don't know the ... I see IntTrie [a] as an infinite collection of lists (well, it is [[a]], after all :-), one for each integer. So I want to take a structure like this:
(1,2):(3,4):(3,5):...
And turn it into a structure like this:
{ 0 -> ... 1 -> 2:... 2 -> ... 3 -> 4:5:... ... }
(This is just a list in my implementation, but I intended it to be a trie, ideally, which is why I wrote the keys explicitly)
So the yet-unknown information at the tail of the list turns into yet-unknown information about the tails of the keys. In fact, if you replace ... with _|_, you get exactly the same thing (this is no coincidence!)
The spine of this trie is maximally lazy: this is key. If the structure of the spine depended on the input data (as it does for Data.Map), then we wouldn't be able to process infinite data, because we can never get it all. So even making a trie out of the list _|_ gives us:
{ 0 -> _|_, 1 -> _|_, 2 -> _|_, ... }
I.e. the keys are still there. Then we can combine two tries just by combining them pointwise (which is what infZipWith does). It is essential that the pattern matches on infZipWith are lazy. We're zipping together an infinite sequence of lists, and normally the result would be the length of the shortest one, which is unknowable. So the lazy pattern match forces the result ('s spine) to be infinite.
Umm... yeah, that's a braindump. Sorry I couldn't be more helpful. I'm happy to answer any specific questions.
Luke
He has kindly provided me with this code:
import Data.Monoid
newtype IntTrie a = IntTrie [a] deriving Show
singleton :: (Monoid a) => Int -> a -> IntTrie a singleton ch x = IntTrie $ replicate ch mempty ++ [x] ++ repeat mempty
lookupTrie :: IntTrie a -> Int -> a lookupTrie (IntTrie xs) n = xs !! n
instance (Monoid a) => Monoid (IntTrie a) where mempty = IntTrie (repeat mempty) mappend (IntTrie xs) (IntTrie ys) = IntTrie (infZipWith mappend xs ys)
infZipWith f ~(x:xs) ~(y:ys) = f x y : infZipWith f xs ys
test = mconcat [singleton (n `mod` 42) [n] | n <- [0..]] `lookupTrie` 10
It's supposed to eventually help me group a list of key value pairs and then further process them in a linear (streaming like) way.
The original list being something like [('a', 23), ('b', 18), ('a', 34) ...].
There are couple of techniques employed in this solution, but I'm just guessing here.
The keywords I've been looking up so far:
Memmoization, Deforestation, Single Pass, Linear Map and some others.
Can someone please fill me in?
Günther
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