
By upgrading, I meant move a function from an IO monad with a config
parameter to a state monad without one.
On Dec 18, 10:52 pm, Bas van Dijk
On 18 December 2011 22:26, Kevin Jardine
wrote: I have a library of functions that all take a config parameter (and usually others) and return results in the IO monad.
It is sometimes useful to drop the config parameter by using a state-like monad..
If you're not modifying the configuration, a reader monad transformer is probably enough:
http://hackage.haskell.org/packages/archive/transformers/0.2.2.0/doc/...
You probably want to define your own monad transformer for your library:
newtype MyMonad m a = M {unM :: ReaderT Config m a} deriving (Functor, Applicative, Monad, MonadTrans, MonadIO)
getConfig :: MyMonad m Config getConfig = M ask
I have found that I can wrap all my functions like so:
withLibrary cfg f = f cfg
This can now be defined as:
withLibrary :: Config -> MyMonad m a -> m a withLibrary cfg m = runReaderT (unM m) cfg
stateF a b c d = getConfig >>= \cfg -> liftIO $ withLibrary cfg libraryF a b c d
notice that I need stateF and libraryF lines, each with n parameters.
Upgrading my library like this is rather tedious.
I would prefer to just write something like
stateF = upgrade libraryF
but I can find no way to define the function upgrade in Haskell.
This must be a fairly common problem. Is there a simple solution?
What do you mean by "upgrading"?
Cheers,
Bas
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