
22 Nov
2004
22 Nov
'04
6:41 a.m.
To my question of
foldlWhile :: (a -> b -> a) -> (a -> Bool) -> a -> [b] -> a foldlWhile f p a bs = case (bs, p a) of ([], _ ) -> a (_, False) -> a (b:bs', _ ) -> foldlWhile f p (f a b) bs'
foldl does not seem to cover this.
Dylan Thurston wrote: On Nov 20, 2004
An alternative is
foldlWhile f p a bs = last $ takeWhile p $ scanl f a bs
Yes. Thank you. Inspecting Prelude, we find out that scanl expresses, mainly, the thing. ----------------- Serge Mechveliani mechvel@botik.ru